13 lines
238 B
Bash
13 lines
238 B
Bash
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#!/usr/bin/env bash
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# 查找 10 以内第一个能整除 2 和 3 的正整数
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i=1
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while [[ ${i} -lt 10 ]]; do
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if [[ $((i % 3)) -eq 0 ]] && [[ $((i % 2)) -eq 0 ]]; then
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echo ${i}
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break;
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fi
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i=`expr ${i} + 1`
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done
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# Output: 6
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