52 lines
1.0 KiB
Python
52 lines
1.0 KiB
Python
|
# 经典递归求解问题:
|
||
|
# 1. 迷宫寻路
|
||
|
# 2. 汉诺塔(梵塔)
|
||
|
# 3. 骑士周游
|
||
|
# 4. 八皇后
|
||
|
|
||
|
|
||
|
def f(n: int, m=1) -> int:
|
||
|
if n == 0 or n == 1:
|
||
|
return m
|
||
|
return f(n - 1, n * m)
|
||
|
|
||
|
|
||
|
def sum(n: int) -> int:
|
||
|
if n == 1:
|
||
|
return 1
|
||
|
return n + sum(n - 1)
|
||
|
|
||
|
|
||
|
def steps(n: int, m={}) -> int:
|
||
|
if n < 0:
|
||
|
return 0
|
||
|
elif n == 0:
|
||
|
return 1
|
||
|
else:
|
||
|
try:
|
||
|
return m[n]
|
||
|
except:
|
||
|
m[n] = steps(n - 1) + steps(n - 2) + steps(n - 3)
|
||
|
return m[n]
|
||
|
|
||
|
|
||
|
def list_depth(items: list) -> int:
|
||
|
max_depth = 1 if isinstance(items, list) else 0
|
||
|
if max_depth:
|
||
|
for item in items:
|
||
|
if isinstance(item, list):
|
||
|
max_depth = max(max_depth, list_depth(item) + 1)
|
||
|
return max_depth
|
||
|
|
||
|
|
||
|
|
||
|
def main():
|
||
|
mylist = [1, ['a', ['b', ['c']]],[100, [200, 300, [400, [500, [600, [700]]]]]]]
|
||
|
thylist = [[], [[[]]], [[], []]]
|
||
|
print(list_depth(mylist))
|
||
|
print(list_depth(thylist))
|
||
|
|
||
|
|
||
|
if __name__ == '__main__':
|
||
|
main()
|