Fix how to get image ID on offline deployment (#7808)
Previously IDs of container images were gotten from tar files of container images but that way was wrong. If multiple json files are contained in a tar file, the script got multiple IDs and tried to pass these IDs on `docker tag` command. Then the command was failed. This updates the script to get image IDs from `docker image inspect` command to fix this issue. In addition, this adds a check a registry container exists already or not before deploying registry container to avoid a container conflict failure.pull/7833/head
parent
627a06e30d
commit
8f44cd35d8
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@ -100,19 +100,27 @@ function register_container_images() {
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tar -zxvf ${IMAGE_TAR_FILE}
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sudo docker load -i ${IMAGE_DIR}/registry-latest.tar
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sudo docker run --restart=always -d -p 5000:5000 --name registry registry:latest
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set +e
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sudo docker container inspect registry >/dev/null 2>&1
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if [ $? -ne 0 ]; then
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sudo docker run --restart=always -d -p 5000:5000 --name registry registry:latest
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fi
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set -e
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while read -r line; do
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file_name=$(echo ${line} | awk '{print $1}')
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org_image=$(echo ${line} | awk '{print $2}')
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new_image="${LOCALHOST_NAME}:5000/${org_image}"
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image_id=$(tar -tf ${IMAGE_DIR}/${file_name} | grep "\.json" | grep -v manifest.json | sed s/"\.json"//)
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raw_image=$(echo ${line} | awk '{print $2}')
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new_image="${LOCALHOST_NAME}:5000/${raw_image}"
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org_image=$(sudo docker load -i ${IMAGE_DIR}/${file_name} | head -n1 | awk '{print $3}')
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image_id=$(sudo docker image inspect ${org_image} | grep "\"Id\":" | awk -F: '{print $3}'| sed s/'\",'//)
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if [ -z "${file_name}" ]; then
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echo "Failed to get file_name for line ${line}"
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exit 1
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fi
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if [ -z "${raw_image}" ]; then
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echo "Failed to get raw_image for line ${line}"
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exit 1
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fi
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if [ -z "${org_image}" ]; then
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echo "Failed to get org_image for line ${line}"
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exit 1
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